Question

1/tan 2/3+ 1/tan 3/7
​

Answer 1

Answer:

Given : Mass of the motorcar, M=1200kg

Initial velocity of the car, u=90 km/h=25 m/s (∵1km/h=

18

5

m/s)

Final velocity of the car, v=18 km/h=5 m/s

Time taken t=4 s

ΔP=mv−mu

ΔP=1200×5−1200×25=−24000 kg m/s

v=u+at

5=25+a×4

⟹a=−5 m/s

2

(-ve shows retardation)

∣F∣=m∣a∣=1200×5=6000 N

Step-by-step explanation:

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Answer 2

Answer:

1/tan 2/3+ 1/tan 3/7

-1.15473145404