Question

1-tan^2 45/1+tan^2 45

Answer 1

Answer:

$Value \: of \: \frac{1-tan^{2}45}{1+tan^{2}45}=0$

Step-by-step explanation:

$Value \: of \: \frac{1-tan^{2}45}{1+tan^{2}45}\\=\frac{1-1}{1+1}$

\* We know that

tan45° = 1*/

$=\frac{0}{2}\\=0$

Therefore,.

$Value \: of \: \frac{1-tan^{2}45}{1+tan^{2}45}=0$

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Answer 2

Step-by-step explanation:

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