Question

1-tan^2(45- theta)/1+tan^2(45 degree-theta)=
(a)sin2 theta
(b)cos2 theta
(c) tan2 theta
(d) cot 2theta​

Answer 1

Step-by-step explanation:

Answer:

Value \: of \: \frac{1-tan^{2}45}{1+tan^{2}45}=0Valueof

1+tan

2

45

1−tan

2

45

=0

Step-by-step explanation:

\begin{gathered}Value \: of \: \frac{1-tan^{2}45}{1+tan^{2}45}\\=\frac{1-1}{1+1}\end{gathered}

Valueof

1+tan

2

45

1−tan

2

45

=

1+1

1−1

\* We know that

tan45° = 1*/

\begin{gathered}=\frac{0}{2}\\=0\end{gathered}

=

2

0

=0

Therefore,.

Value \: of \: \frac{1-tan^{2}45}{1+tan^{2}45}=0Valueof

1+tan

2

45

1−tan

2

45

=0

•••♪