Question

1+tan^2 A/1-tan^2 A = Sec2A
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Answer 1

Step-by-step explanation:

The above explanation is needed to solve this..Please mark it as brainliest....

Answer 2

Step-by-step explanation:

formula, cos2A= (1-tan^2A)/(1+tan^2A)

LHS, (1+tan^2A)/(1-tan^2)=1/cos2A

and cosA=1/secA,

= sec2A (RHS)