1-tan-^2 theta/1+tan^2= 1/2 then theta is equal to
Answers
Answered by
0
Answer:
tan∅ + 1/tan∅ = 2 (Square on both sides)
(tan∅ + 1/tan∅)² = 2² tan²∅ + 1/tan²∅ +2(tan∅×1/tan∅) = 4 tan²∅ + 1/tan²∅ + 2 = 4 tan²∅ + 1/tan²∅ = 4 - 2 tan²∅ +1/tan²∅ = 2
I hope this will help you
Similar questions