Question

1+ Tan 20) (1-sin2o)​

Answer 1

Answer:

$(1 + {tan}^{2} \alpha )(1 - {sin}^{2} \alpha ) \\ = {sec}^{2} \alpha . {cos}^{2} \alpha \\ = \frac{1}{ {cos}^{2} \alpha } \times {cos}^{2} \alpha \\ = 1$