Math, asked by sardarshek622, 4 months ago



1+ Tan 20) (1-sin2o)​

Answers

Answered by sandy1816
2

Answer:

(1  +  {tan}^{2}  \alpha )(1 -  {sin}^{2}  \alpha ) \\  =  {sec}^{2}  \alpha . {cos}^{2}  \alpha  \\  =  \frac{1}{ {cos}^{2}  \alpha }  \times  {cos}^{2}  \alpha  \\  = 1

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