1+tan^2°/cos^2°=sec^2° P.T
Answers
Answered by
0
Answer:
LHS = tan
2
θcos
2
θ
=
cos
2
θ
sin
2
θ
×cos
2
θ
=sin
2
θ
=1−cos
2
θ
=RHS
Step-by-step explanation:
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Answered by
4
Answer:
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