Question

1+tan^2A + {1+1/tan^2A} ​

Answer 1

Answer:

here your answer

Step-by-step explanation:

you meant

$1+tan^2A + [1+ \frac{1}{tan^2A} ]$

$=1+tan^2A+1+cot^2A$     [∵$\frac{1}{tan^2A} = cot^2A$]

$=2+\frac{sin^2A}{cos^2A}+\frac{cos^2A}{sin^2A}$

$=\frac{sin^4A+cos^4A}{sin^2Acos^2A} +2$

$=\frac{(sin^2A+cos^2A)^2-2sin^2Acos^2A}{sin^2Acos^2A}+2$

$=\frac{1-2sin^2Acos^2A}{sin^2Acos^2A}+2$

$=\frac{1}{cos^2A} . \frac{1}{sin^2A} -2+2$

$=sec^2A . cosec^2A$

hey. really i didnt copy :( really im maths expert :(