Math, asked by ranish1357, 1 year ago

1+tan^2a/1+cot^2a= 1+tan^2a

Answers

Answered by santukumar1806
0

your question are wrong brother

right question 1+tan^2a/1+cot^2a=tan^2a

from LHS

= 1+tan^2a/1+cot^2a

= sec^2a/cosec^2a

= 1/cos^2a/1/sin^2a

= sin^2a/cos^2a

= tan^2a

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