Question

(1+tan^2A/1+cot^2A)=(1-tanA/1-cotA)^2=tan^2A.
plz solve !​

Answer 1

Hi there here's your answer

Hope it helps

Answer 2

now let angle be beta or alpha because in answer key board there is no capital letter for A

$\frac{1 + \tan( { \alpha }^{2} ) }{1 + \cot( { \alpha }^{2} ) }$

$= \frac{1 + \tan( { \alpha }^{2} ) }{1 + \frac{1}{ \tan( { \alpha }^{2} ) } }$

$= \frac{1 + \tan( { \alpha }^{2} ) }{ \frac{ \tan( { \alpha }^{2} + 1 ) }{ \tan { \alpha }^{2} } }$

$= \tan( { \alpha }^{2} )$

=RHS
make it as branliest answer

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