Question

(1-tan^2A/1-cot^2A)=tan^2A

Answer 1

Hey mate here is your answer..................

(1-tan²A/1-cot²A) = tan²A

LHS= (1-sin²A/cos²A)/(1-cos²A/sin²A)

      = (cos²A-sin²A/cos²A)/(sin²-cos²A/sin²A)

      = sin²A(cos²A-sin²A)/cos²A(sin²A-cos²A)

     = -sin²A(sin²A-cos²A)/cos²A(sin²A-con²A)

     = -tan²A

HOPE IT HELP YOU...................:)