(1-tan^2A/1-cot^2A)=tan^2A
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Hey mate here is your answer..................
(1-tan²A/1-cot²A) = tan²A
LHS= (1-sin²A/cos²A)/(1-cos²A/sin²A)
= (cos²A-sin²A/cos²A)/(sin²-cos²A/sin²A)
= sin²A(cos²A-sin²A)/cos²A(sin²A-cos²A)
= -sin²A(sin²A-cos²A)/cos²A(sin²A-con²A)
= -tan²A
HOPE IT HELP YOU...................:)
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