Math, asked by aditya2012041342, 2 months ago

1+tan^2A/1+sec^2A=secA

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Answered by saher2020

Answer:

i can't understand the question properly because i didn't get that 1 at the starting is in numerator or a normal 1. provide photo of the question

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1+tan^2A/1+sec^2A=secA​

Answers

1+tan^2A/1+sec^2A=secA