1 + tan^2A + 1 - tan^2A = 2sec^2A
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Answer: MARK THIS AS BRAINLIEST
Step-by-step explanation:
LHS
= (1 + tan²A)/(1 − tan²A)
= sec²A/(1 - sin²A/cos² A)
= sec²A/(cos² A - sin²A)/cos² A
= (sec²A cos² A)/(cos² A - sin²A)
= 1/(cos² A - sin²A)
= 1/cos 2A
= sec 2A = RHS
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