Math, asked by Avinashshirsat3571, 8 months ago

1 + tan^2A + 1 - tan^2A = 2sec^2A

Answers

Answered by tejaspaunikar2716
0

Answer: MARK THIS AS  BRAINLIEST

Step-by-step explanation:

LHS

= (1 + tan²A)/(1 − tan²A)

= sec²A/(1 - sin²A/cos² A)

= sec²A/(cos² A - sin²A)/cos² A

= (sec²A cos² A)/(cos² A - sin²A)

= 1/(cos² A - sin²A)

= 1/cos 2A

= sec 2A = RHS

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