1-tan^2A / 1+tan^2A= cot^2A-1 / cot^2A+1
Answers
Answered by
0
Answer:
Simplifying the LHS of
cot
2
A−1
1−tan
2
A
=tan
2
A.
cot
2
A−1
1−tan
2
A
=
sin
2
A
cos
2
A
−1
1−
cos
2
A
sin
2
A
=
sin
2
A
cos
2
A−sin
2
A
cos
2
A
cos
2
A−sin
2
A
=
cos
2
A
sin
2
A
=tan
2
A
=RHS
Step-by-step explanation:
pl mark it as a brainliest answer
Answered by
7
Answer:
see image for explaination.
Attachments:
Similar questions