Math, asked by umaira1234khanam, 11 months ago

1-tan^2A÷cot^2A-1=tan^2A

Answers

Answered by girijasingh2107

4

Step-by-step explanation:

LHS = 1- 1\cot^2A÷cot^2A-1

=(cot^2A-1)/cot^2A÷cot^2A-1

= 1\cot^2A

= tan^2A = RHS

(hence proved)

please give me thanks

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