Math, asked by mihirk17, 8 months ago

1+tan^2o/1+cot^2o= ( 1-tano/1-coto)^2

Answers

Answered by jtg07

Step-by-step explanation:

L.H.S=

➡️1+tan²o/1+cot²o

➡️(1+sin²o/cos²o)/(1+cos²o/sin²o)

➡️(cos²o+sin²o/cos²o)/(sin²o+cos²o/sin²o)

➡️( 1/cos²o )/( 1/sin²o )

➡️(tan²o)

R.H.S

➡️(1-tano)/1-coto)²

➡️( 1+tan²o-2tano)/(1+cot²o-2coto)

➡️(tan²o)

➡️hence,proved

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Answered by khushi02022010

Answer:

What is the simplified value of 1 + tan A tan (A/2) ? so the answer is option C.

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1+tan^2o/1+cot^2o= ( 1-tano/1-coto)^2​

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1+tan^2o/1+cot^2o= ( 1-tano/1-coto)^2