Question

1+tan^2theta/1+cot^2theta=sin^2theta/cos^2theta=tan^2theta

Answer 1

Step-by-step explanation:

Consider theta = x

=(1+tan²x)/(1+cot²x)

=sec²x/cosec²x.

(Identity)

=sin²x/cos²x.

(secx=1/cosx & cosecx=1/sinx)

=tan²x.

(sinx/cosx=tanx).