(1÷Tan 3A+TanA) + (1÷Cot 3A +Cot A) = 1÷2cosec 2A
Answers
Answered by
1
Step-by-step explanation:
Given,
tan3A−tanA
1
−
cot3A−cotA
1
=kcot2A
LHS=
cos3A
sin3A
−
cosA
sinA
1
−
sin3A
cos3A
−
sinA
cosA
1
=
sin2A
cos3AcosA
+
sin2A
sin3AsinA
=cot2A
So, k=1
Similar questions
Math,
3 months ago
Computer Science,
3 months ago
English,
3 months ago
Hindi,
6 months ago
Math,
6 months ago