Math, asked by sureshlimbu72, 7 months ago

(1÷Tan 3A+TanA) + (1÷Cot 3A +Cot A) = 1÷2cosec 2A

Answers

Answered by ganjankumarsahu8

1

Step-by-step explanation:

Given,

tan3A−tanA

1

−

cot3A−cotA

1

=kcot2A

LHS=

cos3A

sin3A

−

cosA

sinA

1

−

sin3A

cos3A

−

sinA

cosA

1

=

sin2A

cos3AcosA

+

sin2A

sin3AsinA

=cot2A

So, k=1

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