Question

1 + tan 45°=sec square ...........?

Answer 1

Proof:

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Here , we are using

i ) tanA = sinA/cosA

ii) sin²A + cos²A = 1

iii) 1/cosA = secA

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Now,

LHS = 1+tan²A

= 1 + (sin²A/cos²A)

= (cos²A+sin²A)/cos²A

= 1/cos²A

= sec²A

= RHS

••••

Answer 2

Hey!

Refer the below attachment !

Thanks !