Question

1+ tan^A/1+cot^A
plz ans fast.........​

Answer 1

Using the following identities,

$1 + { \tan }^{2 } \alpha = { \sec }^{2} \alpha$
and

$1 + { \cot }^{2} \alpha = { \csc }^{2} \alpha$


Using these two values, in the given equation,

$\frac{ { \sec }^{2} \alpha }{ { \csc}^{2} \alpha } \\ \\ = \frac{ { \sin }^{2} \alpha }{ { \cos }^{2} \alpha } \\ \\ = { \tan}^{2} \alpha$

Tada!