Math, asked by bhisepratik695, 2 months ago

1
tan A
1 + SecA
1 + SECA
tana
is equal to

Answers

Answered by ankit3026

3

Answer:

−

1−secA

tanA

=2⋅cosecA

L.H.S

1+secA

tanA

−

1−secA

tanA

=

1−sec

2

A

tanA(1−secA)−tanA(1+secA)

=

−tan

2

A

tanA(1−secA−1−secA)

=

−tanA

−2secA

=

sinA/cosA

2⋅1/cosA

=

sinA

2

=2⋅cosecA

=R.H.S

∴ L.H.S=R.H.S.

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