Question

1/(tan A + cotA)
= cos A sin A​

Answer 1

Step-by-step explanation:

Hope it helps !!!!!!!!

Answer 2

Step-by-step explanation:

Given,

1/(tanA+cotA) = cosA.sinA

Now consider,

L.H.S,

1/(tanA+cotA)

=> 1/[(sinA/cosA + cosA/sinA)]

=> 1/[(sin²A+cos²A)/(cosA.sinA)]

=> 1/(1/cosA.sinA)

(Since Sin²∅+Cos²∅ = 1 identity)

=> 1 × cosA.sinA/1

=> cos.sinA/1

=> cosA.sinA

= R.H.S.

I hope it helps you.