(1+tan A tan B)²+(tan A -tan B)² =Sec²A Sec²B
Prove it
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Step-by-step explanation:
( 1 + tan²A*tan²B + 2tanA*tanB ) +
( tan²A + tan²B - 2tanA*tanB)
= 1 + tan²A*tan²B + tan²A + tan²B
= (1 + tan²A) + tan²B( 1 + tan²A )
= ( 1 + tan²A ) ( 1 + tan²B )
= Sec²A * Sec²B
Hence proof
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