Question

(1 - tan A) to power 2 + (1 + tan A) to power 2 = 2 sec square A​

Answer 1

Answer:

(1-tanA)^2+(1+tanA)^2

2(tan^2+a)

2secA^2

Step-by-step explanation:

Answer 2

lhs

{1-tanA}^2+{1+tanA}^2

1+ tan^2A - 2tanA + 1 + tan^2A+ 2tanA

1 + tan^2A + 1 + tan^2A + 2tanA - 2tanA

2{1 + tan^2 A}

2 sec^2 A.

{because 1 + tan^2A= sec^2A}

LHS = RHS

SO PROVED