(1+tan+sec)(1+cot-cosec)
Find out
With step by step
Answers
Answered by
1
(1+cot A-cosec A).(1+tanA+secA)
(1+cosA/sinA-1/sinA).(1+sinA/cosA+1/cosA)
(sinA+cosA-1)×(cosA+sinA+1)/sinA.cosA
[(sinA+cosA)^2-(1)^2]/sinA.cosA.
(sin^2A+cos^2A+2.sinA.cosA-1)/sinA.cosA.
( 1+2.sinA.cosA -1)/sinA.cosA.
2.sinA.cosA/sinA.cosA
2
Hope it will help you.
Mark as brainliest...
(1+cosA/sinA-1/sinA).(1+sinA/cosA+1/cosA)
(sinA+cosA-1)×(cosA+sinA+1)/sinA.cosA
[(sinA+cosA)^2-(1)^2]/sinA.cosA.
(sin^2A+cos^2A+2.sinA.cosA-1)/sinA.cosA.
( 1+2.sinA.cosA -1)/sinA.cosA.
2.sinA.cosA/sinA.cosA
2
Hope it will help you.
Mark as brainliest...
Answered by
5
Therefore, answer is 2
Attachments:
Anonymous:
thnks for answer
xd
Similar questions