Math, asked by somdeb85, 3 months ago

1 - tan sq 30/ 1+ tansq 30

Answers

Answered by Gauthmathspark
0

 \frac{1 -  { \tan(30) }^{2} }{1 +  { \tan(30) }^{2} }  \\  =  \frac{1 -  ({ \frac{1}{ \sqrt{3} }) }^{2} }{1 +  ({ \frac{1}{ \sqrt{3} }) }^{2} }   \\  =  \frac{1 -  \frac{1}{3} }{1 +  \frac{1}{3} }  \\  =  \frac{ \frac{2}{3} }{ \frac{4}{3} }  =  \frac{1}{2}

Answered by Gauthmath

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