1+tan square A / 1+cot square = 1-tanA /
1-cotA
Attachments:
Answers
Answered by
1
Answer:
LHS= 1+Tan²A/1+cot²A = sec²A/cosec²A
= 1/cos²A/1/sin²A
= sin²A/cos²A = tan²A
RHS= (1 - tanA/1-cotA)² = (1 - tanA/1-1/tanA)²
= (1-tanA/tanA-1/tanA)²
= - (1+tanA/tanA-1 × tanA)²
= ( -1× tanA)² = tan²A
LHS=RHS....
HOPE IT HELP YOU!!!!
Similar questions