Question

(1+tan square theta ) (1-cos square theta) = ______

Answer 1

$hello! \\ \\ (1 + { \tan }^{2} theta)(1 - { \cos}^{2} theta) = \\ \\ { \sec}^{2} theta)( {sin}^{2} theta) \\ \\ since \: 1 + { \tan}^{2} theta = { \sec }^{2} theta \\ \\ and \: 1 - { \cos}^{2} theta = { \sin }^{2} theta \\ \\ also \: we \: know \: \sec(theta) \: = 1 \div \cos(theta) \\ \\ ie. {sin}^{2} theta \times 1 \div { \cos }^{2} theta \\ \\ = { \tan }^{2} theat \: \:is \: the \: correct \: answer \\ \\ hope \: this \: will \: help \: u...$