Question

1 + tan square theta * 1 + sin theta*1 minus sin theta = 1​

Answer 1

Answer:

let theta=A

Step-by-step explanation:

LHS

=(1+tanA ^2)*(1+sinA)*(1-sinA)

=(1+tanA^2)*(1-sinA^2)

=(secA^2)*(cosA^2). (1+tanA^2=secA^2 & 1-sinA^2=cosA^2)

=(1/cosA^2)*cosA^2. (secA=1/cosA)

=1=RHS proved

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