Question

1+tan square theta =​

Answer 1

✍✍✍✍. answer. ✍✍✍

$we \: know \: that \\ \\ {sec}^{2} \alpha - {tan}^{2} \alpha = 1 \\ = > {sec}^{2} \alpha = 1 + {tan}^{2} \alpha$

so the answer is sec^2 theta ✔✔✔

✨✨hope it helps✨✨