Question

1 + tan square theta into sin square theta is equal to​

Answer 1

Answer:

=(1+tan square theta) (sin square theta)

=sin square theta into sec square theta

=sin square theta into 1/cos square theta

=sin square theta / cos square theta

=tan square theta

Hope it helps you ;)

Answer 2

$(1 + { \tan}^{2} \alpha) \times ( { \sin}^{2} \alpha ) \\ = sec {}^{2} \alpha . \: { \sin }^{2} \alpha \\ = \frac{ { \sin }^{2} \alpha }{ { \cos }^{2} \alpha } \\ = \tan^{2} \alpha$