Math, asked by kalsanggaga1950, 11 months ago

1-tan squaredA divided by 1+cot squared A

Answers

Answered by aamahiss
1

Answer:

1-tan^2A/1+cot^2A

=1-tan^2A/cosec^2A

=1-tan^2A/1/sin^2A

=[1-tan^2A] sin^2A

=sin^2A-sin^4A/cos^2A

and it continues on

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