Question

1+tan squreA÷1+cot square A=?

Answer 1

Tan square A



this is the answer

Answer 2

Hi ,

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We know the trigonometric identity

1 ) 1 + tan²A = sec² A

2 ) 1 + cot² A = cosec² A

3 ) secA = 1/cosA

4 ) cosecA = 1/sinA

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Here ,

( 1 + tan² A ) / ( 1 + cot² A )

= Sec² A/cosec² A

= ( 1/cos² A ) / ( 1/sin² A )

= Sin² A / cos² A

= Tan² A

Or

Method ( 2 ) :

( 1 + tan² A ) / ( 1 + cot² A )

= ( 1 + tan² A ) / ( 1 + 1/tan² A )

= ( 1+ tan² A ) [ ( tan² A + 1 ) / tan² A ]

After cancellation ,

= tan² A

I hope this helps you.

:)