Question

1+tanα.tan(2α)=sec(2α)​

Answer 1

Answer:

Answer

Now,

1+tanα.tan2α

=1+tanα.

1−tan

2

α

2tanα

[ Using formula for tan2α]

=

1−tan

2

α

1+tan

2

α

=

cos

2

α−sin

2

α

cos

2

α+cos

2

α

=

cos2α

1

=sec2α.

Answer 2

Answer:

the answer to above question is in the photo