Math, asked by pilsujghosh, 11 hours ago

(1 - Tan theta / 1+tan theta)^2= tan^2 theta​

Answers

Answered by GιяℓуSσυℓ
1

Answer:

tan∅ + 1/tan∅ = 2

Square on both sides,

(tan∅ + 1/tan∅)²

= 2² tan²∅ + 1/tan²∅ +2(tan∅×1/tan∅)

= 4 tan²∅ + 1/tan²∅ + 2

= 4 tan²∅ + 1/tan²∅

= 4 - 2 tan²∅ +1/tan²∅ = 2

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