(1 - Tan theta / 1+tan theta)^2= tan^2 theta
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Answer:
tan∅ + 1/tan∅ = 2
Square on both sides,
(tan∅ + 1/tan∅)²
= 2² tan²∅ + 1/tan²∅ +2(tan∅×1/tan∅)
= 4 tan²∅ + 1/tan²∅ + 2
= 4 tan²∅ + 1/tan²∅
= 4 - 2 tan²∅ +1/tan²∅ = 2
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