Question

1+tan theta + sec theta (1+ cot theta -cosec theta)

Answer 1

1+tan+sec(1+cot-cosec)

Step-by-step explanation:

=1+sin/cos+1/cos*(1+cos/sin-1/sin)

=1+ (sin+1/cos)*(1+(cos-1/sin))

=((cos+sin+1)/cos)*((sin+cos-1)/sin)

by multiplying both we get

=((sin*cos)+cos^2-cos+sin^2+(sin*cos)-sin+sin+cos-1)/sin*cos

=(2sin*cos+sin^2+cos^2-1)/sin*cos

by the standard results (sin^2+cos^2)=1

we get

=((2sin*cos)+1-1)/sin*cos

=(2sin*cos)/sin*cos

=2 answer