(1-tan thita/1-cotthita)^2=1+tan^2thita/1+cot^2thita. plzzz solve detail
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Answer:
L:H:S
(1- tanØ/1-cotØ)²
= (cos Ø-sinØ/cosØ/sinØ-cosØ/sinØ)
={-sinØ(sinØ-cosØ)/cosØ(sinØ-cosØ)}²
= {-sinØ/cosØ}²
=tan²Ø
R:H:S
1+tan²Ø/1+cot²Ø
= sec²Ø/cosec ²Ø
=(sin/cos)²
=tan²Ø
hence prooved
hope it helps ✨✨
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