(1+tan0+cot0)(sin0-cos0)=[sec0/cosec²0-cosec0/sec²0]
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I think the rhs of the question is incorrect.
bt here is Ur solution.
bt here is Ur solution.
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Titiks80:
No HER is absolutely correct .Refer to the solution below:)
Answered by
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L.H.S = (1+TAN0+COT0)(SIN0-COS0) =(1+SIN/COS+COS/SIN)(SIN-COS) =
(COSSIN+SIN^2+COS^2/COSSIN)(SIN-COS) =
COSSIN^2-COS^2SIN+SIN^3-SIN^2COS+COS^2SIN-COS^3/COSSIN
=SIN^3 -COS^3/COSSIN =
R.H.S =
SEC/COSEC^2-COSEC/SEC^2 =
1/COS/1/SIN^2 -1/SIN/1/COS^2
=SIN^3-COS^3/SINCOS .
LHS=THE HENCE PROVED
(COSSIN+SIN^2+COS^2/COSSIN)(SIN-COS) =
COSSIN^2-COS^2SIN+SIN^3-SIN^2COS+COS^2SIN-COS^3/COSSIN
=SIN^3 -COS^3/COSSIN =
R.H.S =
SEC/COSEC^2-COSEC/SEC^2 =
1/COS/1/SIN^2 -1/SIN/1/COS^2
=SIN^3-COS^3/SINCOS .
LHS=THE HENCE PROVED
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