1+tan2/1+secA =secA
Please help me
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Answer:
Step-by-step explanation:1+
1+secA
tan
2
A
=1+
1+secA
(sec
2
A−1)
=1+
(1+secA)
(secA−1)(secA+1)
=1+secA−1
=secA
⇒1+
1+secA
tan
2
A
=secA.
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