Question

(1+ tan2 60)2 is equal to

1
16
2
4​

Answer 1

$1 + ta {n}^{2} \theta \: = se {c}^{2} \theta$

$( {1 + tan}^{2} 6 {0)}^{2} = (se {c}^{2} \: 6 {0)}^{2} \\ = { (({2})^{2}) }^{2} \\ = {(4)}^{2} \\ = 16$

B) 16 is the answer ✔️