Question

1 + tan² A/1+ Cot²A = ?
a)-1 b) Seca c) tan’a d) Cot’A​

Answer 1

Answer:

(d)cot²A

Step-by-step explanation:

$\frac{ 1 + \frac{ {cos}^{2} a}{ {sin}^{2} a} }{1 + \frac{ {sin}^{2} a}{ {cos}^{2} a} } = \frac{ \frac{ {sin}^{2}a + {cos}^{2} a}{ {sin}^{2} a} }{ \frac{ {cos}^{2} a + {sin}^{2} a} { {cos}^{2}a } } = \frac{\frac{1}{ {sin}^{2} a}} { \frac{1}{ {cos}^{2} a} } \\ \\ \\ = \frac{ {cos}^{2}a }{ {sin}^{2} a} = {cot}^{2}a \\ \\ tan = \frac{sinA}{CosA } \: \: \: \: and \: (cos \: = \frac{cosA}{SinA})$

sin²A+cos²A=1