Question

(1 + Tan²-A) (1 - Sin³A) = 1 show that​

Answer 1

Answer:

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Step-by-step explanation:

Identity : sec2A−tan2A=1

LHS=(1+tan2A)(1+tan2A1)

           =(sec2A)tan2Asec2A

            =cos2A1cos2Asin2Acos2A1

           =sin2Acos2A1

           =sin2A(1−sin2A)1

           =sin2A−sin4A1

           =RHS