1 - tan²∅/ cot²∅-1 = tan²∅
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To Prove → (1 - tan²A)/(cot²A - 1) = tan²A
L.H.S → (1 - tan²A)/(cot²A - 1)
Since we know that,
cot ∅ = 1/tan∅
Denominator → (1/tanA)² - 1
→ 1/tan²A - 1
→ (1 - tan²A)/tan²A
Numerator/Denominator
→ (1 - tan²A)/(1 - tan²A)/tan²A
→ tan²A = R.H.S
Hence L.H.S and R.H.S are equal
Hence Proved
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