(1+tan2 theta) cot/cosec2 =tan theta
Answers
Answered by
1
Step-by-step explanation:
Let theta =A
( 1- tan^2A)/(cof^2A-1)= tan^2A
L.H.S.
=(1-tan^2A)/(cot^2A-1)
=(1-tan^2A)/( 1/tan^2A. - 1)
=(1-tan^2A)/{(1-tan^2A)/tan^2A}
=(1-tan^2A)×tan^2A/(1-tan^2A)
= tan^2A. Proved.
Answered by
1
Answer:
(tanθ+cotθ)
2
=sec
2
θ+cosec
2
θ
L.H.S (tanθ+cotθ)
2
=tan
2
θ+cot
2
θ+2tanθcotθ
=sec
2
θ−1+cosec
2
θ−1+2tanθ
tanθ
1
=sec
2
θ+cosec
2
θ−2+2
=sec
2
θ+cosec
2
θ
=R.H.S.
Step-by-step explanation:
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