Question

(1+tan²0) is equal to
$a. tan{}^{2} \: 0$
$b.sec {}^{2} \: 0$
$c. - sec {}^{2} \: 0$
$d.0$
​

Answer 1

answer:

sec^2\:0

step to step explain

tan^2\: 0 + 1 = sec^2\:0

Answer 2

Answer:

sec^2\:0

tan^2\:0 + 1 = sec^2\:0

Step-by-step explanation:

Hope this answer will help you dear...