Question

(1+tan2a) + (1+1/tan a) = 1/sin2a-sin4a

Answer 1

Answer:

Identity : sec

2

A−tan

2

A=1

LHS=(1+tan

2

A)(1+

tan

2

A

1

)

=(sec

2

A)

tan

2

A

sec

2

A

=

cos

2

A

1

cos

2

A

sin

2

A

cos

2

A

1

=

sin

2

Acos

2

A

1

=

sin

2

A(1−sin

2

A)

1

=

sin

2

A−sin

4

A

1

=RHS

Hence proved