Question

(1+tan2a) + (1+1/tan2a) = 1/sin2a-sin4a

Answer 1

The answer won't be equal to RHS 
it will be equal if  the question is:
 (1 + 1/tan²A)(1 + 1/cot²A) = 1/(sin²A - sin^4.A)
LHS 
= (1 + 1/tan²A)(1 + 1/cot²A) 
= ((tan²A+1)/tan²A)((cot²A+1)/cot²A) 
= (sec²A/tan²A)(csc²A/cot²A) 
= (sec²A.csc²A)/(tan²A.cot²A) 
= sec²A.csc²A 
= 1/(sin²A.cos²A) 
= (1/sin²A)(1/cos²A) 
= (1/sin²A)(1/(1-sin²A)) 
= 1/(sin²A - sin^4.A) 
= RHS

Answer 2

plzz mark brainliest