Question

(1+tan²A)/(1+cot²A) = *

1 point

a) sec²A

b) -1

c) cot²A

d) tan²A

​

Answer 1

$\frac{1 + {tan}^{2} A}{1 + {cot}^{2}A }$

$\frac{ {sec}^{2}A}{ {cosec}^{2} A}$

$\frac{ \frac{1}{ {cos}^{2}A} }{ \frac{1}{ {sin}^{2}A } }$

$\frac{ {sin}^{2} A}{ {cos}^{2}A }$

${tan}^{2} A$

#FollowMe

Answer 2

Answer:

the answer is1

Step-by-step explanation:

1+ tan^2A/1+cot^2 Acan be written as

1+tan^2A/tan^2+1

=1