(1+tan2a) (1-sin2a) (1+sin2a) = 1
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(1 + sin^2a/cos^2a)(1-sin^2a)
cos^2a + sin^2a/cos^2a * cos^a
1
cos^2a + sin^2a/cos^2a * cos^a
1
rishabkeswani3p96fuo:
it is wrong ! no offense.
Bro its correct
bro 1+ tan2 a is sec2a
if you change tan into sin/cos you will get the same
butcan you do it this way please this is my homework
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