Question

1-tan²A/cot2A-1=tan²A

Answer 1

Answer:

(1+tan2A)/(1+cot2A) =tan2A

L.H.S.

(1+tan2A) = sec2A = (1/cos2A)

(1+cot2A) = cosec2A = (1/sin2A)

(1/cos2A) / (1/sin2A) =1/cos2A×sin2A =sin2A/cos2A =tan2A

L.H.S. =R.H.S

( NOTE : 2 MEANS SQUARE OR POWER 2)